Question

if a =1 b=2 c=3 then find 5a²+ 6bc-3ab​

Answer 1

Given: a =1, b=2, c=3

So, 5a²+ 6bc-3ab = 5(1)² + 6(2)(3) - 3(1)(2)

= 5 + 36 - 6

= 5 + 30

= 35

∴ 5a²+ 6bc-3ab = 35