Question

if a=1 b= (-2) find the value of a²+ab+b²​

Answer 1

${a}^{2} + ab + {b}^{2} = {(a + b)}^{2}$

$({ - 1})^{2}$

${(1 + ( - 2)})^{2}$

$= 1$

Answer 2

Answer:

3

Step-by-step explanation:

(1)^2+(1)(-2)+(-2)^2

=1-2+4

=3