Question

if a=1,b=2 then find the value of (a^b+b^a)^-1​

Answer 1

Answer:

1/3

Step-by-step explanation:

a=1

b=2

(a^b+b^a)^-1

=(1^2+2^1)^-1

=(1+2)^-1

=3^-1

=1/3

Answer 2

$\displaystyle \sf{ {( {a}^{b} + {b}^{a} )}^{ - 1} } = \frac{1}{3}$

Given :

$\displaystyle \sf{ The \:expression \: \: {( {a}^{b} + {b}^{a} )}^{ - 1} }$

To find :

The value of the expression for a = 1 , b = 2

Solution :

Step 1 of 2 :

Write down the given expression

$\displaystyle \sf{ The \:expression \: is \: \: {( {a}^{b} + {b}^{a} )}^{ - 1} }$

Step 2 of 2 :

Find the value of the expression

Putting a = 1 , b = 2 in the given expression we get

$\displaystyle \sf = {( {1}^{2} + {2}^{1} )}^{ - 1}$

$\displaystyle \sf = {(1 + 2 )}^{ - 1}$

$\displaystyle \sf = {3}^{ - 1}$

$\displaystyle \sf{ = \frac{1}{3} }$

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