Question

if a = 1, b = 28 x = 3; find the value of a+b+c​

Answer 1

Answer:

32

Step-by-step explanation:

a = 1 , b = 28 , c = 3

a + b + c​

1 + 28 + 3

29 + 3

32

Answer 2

$\Large\mathtt\green{ }\huge\underline\mathtt\red{Answer : }$

a3+b3=(a+b)(a2+b2−ab)

(a+b)2=(a2+b2+2ab) or(a+b)2−3ab=(a2+b2−ab)

a3+b3=(a+b)((a+b)2−3ab))=(11)(112−3×28)=407

Hence, a3+b3=407.

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