if a=1+log2-log5,b=2log3,c=log p-log5 and a+b=2c find the value of p
Answers
Answered by
7
Answer:
Formula used
- loga+logb=log(ab)
- loga-logb=log(a/b)
- xlogy=log(y^x)
Step-by-step explanation:
a=1+log2-log5
=log10+log2-log5
=log(5×2)+log2-log5
=log5+log2+log2-log5
=2log2
=log2²
a=log4
b=2log 3
b=log3²
b=log9
c=logp-log5
c=log(p/5)
a+b=2c
log4+log9=2log(p/5)
log(4×9)=log(p/5)²
log36=log(p/5)²
36=(p/5)²
6=p/5
p=30
hope it helps
please mark as branliest
Answered by
1
Answer:
Formula used
loga+logb=log(ab)
loga-logb=log(a/b)
xlogy=log(y^x)
Step-by-step explanation:
a=1+log2-log5
=log10+log2-log5
=log(5×2)+log2-log5
=log5+log2+log2-log5
=2log2
=log2²
a=log4
b=2log 3
b=log3²
b=log9
c=logp-log5
c=log(p/5)
a+b=2c
log4+log9=2log(p/5)
log(4×9)=log(p/5)²
log36=log(p/5)²
36=(p/5)²
6=p/5
p=30
Step-by-step explanation:
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