Question

if a=1-root 7 /1+root 7 and b = 1+root 7/1-root 7 , then find the value of a²+ab+b²/a²-ab+b²​

Answer 1

Answer:

7

+1

7

−1

−

7

−1

7

+1

=a+b

7

(

7

+1)(

7

−1)

(

7

−1)

2

−(

7

+1)

2

=a+b

7

(

7

)

2

−1

2

7+1−2

7

−7−1−2

7

=a+b

7

(

7

)

2

−1

2

7+1−2

7

−7−1−2

7

=a+b

7

0+

3

−2

7

=a+b

7

So, from the above equation,

we can find, a=0 and

3

−2

7

=b

7

b=

3

−2

Answer (C) a=0,b=

3

−2

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Answer 2

Hope this will help you Buddy