Question

If a ≠1, then the value of 1 +(1+a) +(1 +a +a²) =

Answer 1

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Answer 2

=1+1+a+1+a+a^2

=3+2a+ a^2

= a^2+2a+3

use disc. rule ,a=1 , b= 2 ,c= 3

a={ -b +- root (b^2 -4ac) }/2a

= {-2 +- root (4-12)}/2

= { -2 +- 2root2 iota }/2

take 2 common and 2 is cancelled

= -1 +- root 2 iota