if a + 1 upon a equals to under root 5 find the value of 1 upon a power 4 + a power 4
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Hello !!
A + 1/A = ✓5
On squaring both sides , we get ;
( A + 1/A)² = (✓5)²
A² + 1/A² + 2 × A × 1/A = 5
A² + 1/A² + 2 = 5
A² + 1/A² = 5-2
A² + 1/A² = 3
On squaring both sides , we get ;
★ ( A² + 1/A²)² = (3)²
=> A⁴ + 1/A⁴ + 2 × A² × 1/A² = 9
=> A⁴ + 1/A⁴ + 2 = 9
=> A⁴ + 1/A⁴ = 9-2
=> A⁴ + 1/A⁴ = 7
Hence,
1/A⁴ + A⁴ = 7.
A + 1/A = ✓5
On squaring both sides , we get ;
( A + 1/A)² = (✓5)²
A² + 1/A² + 2 × A × 1/A = 5
A² + 1/A² + 2 = 5
A² + 1/A² = 5-2
A² + 1/A² = 3
On squaring both sides , we get ;
★ ( A² + 1/A²)² = (3)²
=> A⁴ + 1/A⁴ + 2 × A² × 1/A² = 9
=> A⁴ + 1/A⁴ + 2 = 9
=> A⁴ + 1/A⁴ = 9-2
=> A⁴ + 1/A⁴ = 7
Hence,
1/A⁴ + A⁴ = 7.
yash8880:
yah you are right thanks
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