Question

If a^1/x = b^1/y = c^1/z and abc = 1, then the value of x + y + z is:​

Answer 1

Answer:

0

Step-by-step explanation:

let a^1/x= b^1/y= c^1/z= k

a= k^x, b= k^y, c= k^z

abc= 1

k^x×k^y×k^z= 1

k^x+y+z= 1= k^0

x+y+z= 0