If a=10,d=10 find s100
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Answered by
8
by using the formula
Sn =n/2[2a+(n-1)d]
S100=100/2[2×10+(100-1)10]
=50(20+990)
=1010×50
=50500
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Answered by
1
Answer:
Hey buddy here is the answer
Sn= n/2(2a+(n-1) d)
= 100/2 (2×10+(100-1)10)
=50(20+99×10)
=50(20+990)
=50(1010)
=50.550
therefore,
the sum of 100 terms in AP is 50,550
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