Question

if a =10 , d=6 then find the sum of 40 terms.​

Answer 1

Answer:

S40=40/2(20+39X6)

S40=20(20+234)

S40=20(254)

S40=5080

Answer 2

Answer:

Here

a=10

d=6

n=40

substitute in eqn

a(n)=a+(n-1)d

a40=10+39*6

10+234

therefore 40th term is 244

Step-by-step explanation:

$sum = \frac{n}{2} (2a + n - 1 \times d)$

substitute value you will get the answer

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