Question

If a 10 digit number 1220x558y2 is divisible by 88, then find the value of x+y

Answer 1

Answer:

hence; 88 ko 2 part mei divide kr sakte hain 11×8

Answer 2

The value of x+y is 9.

Explanation:

The given 10-digit number =  1220x558y2

Since the number is divisible by 88 , and 88= 11 x 8

So the number should be divisible by 8 and 11 too.

Divisibility criteria of 8 : last three digit should be divisible by 8

Here , Last three digit =8y2

The only possible values of y = 3 or 7 ∵  8 divides 832 and 872.

Divisibility criteria of 11 : Difference between the sum of odd places and the sum of even places should be multiple of 11.

If y= 3

So number is 1220x55832

Sum of odd places = 1+2+x+5+3=11+x

Sum of  even places = 2+0+5+8+2= 17

The only possible values of  x = 6 such that difference =0 which is divisble by 11 .

If y= 7

So number is 1220x55872

Sum of odd places = 1+2+x+5+7=15+x

Sum of  even places = 2+0+5+8+2= 17

The only possible values of  x = 2.

So the possible values of x+y are:

When y=3 , x= 6

x+y= 3+6=9

When y=7 , x= 2

x+y= 7+2=9

Hence, the value of x+y is 9.

# Learn more :

In a third digit number the hundreds digit is twice the 10 digit while the unit digit is thrice the 10 digit also the sum of its digit is 18 find the number​

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