If a 10 newton force applied on a 20 kg mass object for a 10 second. the change in momentum will be
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Answer:200
Explanation:
F= 10
ma = 10
m= 20
20 *a = 10
a=.5
u=0
v= u + at
u=0
t = 10 s
v = at
v= .5 *10
V=5m s
Change in momentum
m2v2- m1v1
20 * 5 - 20 *0
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