if a 100 watt bulb emits monochromatic light of energy 5 into 10 power minus 19 joules the number of photons emitted per second by the bulb
Answers
Answered by
0
Answer:
Step-by-step explanation:
Given
if a 100 watt bulb emits monochromatic light of energy 5 into 10 power minus 19 joules the number of photons emitted per second by the bulb
ANSWER
Energy of one photon = E = h c/λ
= 6.626 x 10^- 34 JS x 3 x 10^8 m/s/ 5 x 10^- 19 x 10^- 9 m
= 6.626 x 3 x 10^-26 / 5 x 10^- 28 J
E = 397.56 J
Number of photons emitted per second = 100 J/S / 397.56 J
= 0.2515 s^-1
Similar questions