Question

if a=107, b=13,using Eulid's division algorithm find the values of 'q' and 'r' such that a=bq+r

Answer 1

the value of q=8 and r=3.
proof :
a=bq+r
107= 13(8)+3
107=107

Answer 2

$a = 107, b =13$

Applying the formula  $a = bq + r$ where $a = dividend, b = divisor, q = quotient, r = remainder$

So, when we divide 107 by 13, we get 8 as the quotient and 3 as the remainder.

When we insert those values in the formula,

$107 = 13(8) + 3$

$107 = 104 + 3$

$107 = 107$

so these values satisfy our formula.

Therefore, $q = 8, r = 3$