Question

If a 10m long wire of resistance 12Ω is connected in series with a battery of emf 6V

and a resistance of 3Ω, then the potential gradient along the wire is:
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Answer 1

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Answer 2

$\star\:\:\:\bf\large\underline\blue{Given:—}$

☛︎ Resistance of the battery,R = 12Ω and 3Ω

☛︎ EMF of the better = 6 V

$\star\:\:\:\large\underline\blue{To\:find:—}$

Potential gradient along the wire = ?

$\star\:\:\:\bf\large\underline\blue{Solution:—}$

Total resistance

= 12Ω + 3Ω

= 15Ω

$\boxed{\bf{\red{Formula:—I=\frac{V}{R}}}}$

$➝I=\frac{6}{15}A$

➝I = 0.4 A

Voltage drop along the line

= I×R

= 0.4 × 15 V

= 6 V

Hence, potential gradient

= 6÷12 V/m

= 0.5 V/m

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