Question

If a = -11/27,b=4/9 and c= -5/18, then verify that a+[b+c]=[a+b]+c.

Answer 1

Step-by-step explanation:

Consider LHS:

b+c is 4/9 - 5/18 = (8-5)/18 = 3/18

a+[b+c] = -11/27 + 3/18 = (-22+9)/54 = -13/54

Consider RHS

a+b = -11/27 + 4/9 = (-11+12)/27 = 1/27

a+b+c = 1/27 - 5/18 = (2-15)/54 = -13/54

LHS = RHS. therefore proved.

Answer 2

Answer:

a=−11/27,b=4/9 and c=−5/18

a+(b+c)=(a+b)+c

Consider,

L.H.S.=a+(b+c)

=−11/27+{4/9+(−5/18)}

=−11/27+(4/9−5/18)

On simplification, we get

=−11/27+(8−5)/18

=−11/27+3/18

Taking L.C.M. we get,

=(−22+9)/54

=−13/54

R.H.S.=(a+b)+c

=(−11/27+4/9)+(−5/18)

On further calculation, we get

={(−11+12)/27}+(−5/18)

=(1/27)+(−5/18)

=(2−15)/54

=−13/54

Hence,

L.H.S.=R.H.S.

Step-by-step explanation:

Hope it helps you ✌️✌️