If a, 12, 16 and b are in continued proportion, find a and b?
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Answered by
62
Given that a,12,6,b are in continued proportion.
= > (a/12) = (12/16) = (16/b)
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Now,
= > (12/16) = (16/b)
= > 16 * 16 = 12b
= > 256 = 12b
= > b = 256/12
= > b = 64/3.
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Now,
= > a/12 = 12/16
= > 16a = 144
= > a = 144/16
= > a = 9.
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Therefore, the value of a = 9 and b = 64/3.
Hope this helps!
Answered by
6
Step-by-step explanation:
a/12=12/16
144=16a
- 144/16=a
- a=9
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