if a=12 and b=16 and a+b×c=56.find c and c+a×b.
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Answered by
0
a=12
b=16
so a+(b×c)= 56
12+16×c=56
12+16c=56
16c=56-12
c= 44/16
c= 2.75
b=16
so a+(b×c)= 56
12+16×c=56
12+16c=56
16c=56-12
c= 44/16
c= 2.75
Answered by
1
★★HEYA FRIEND HERE IS YOUR ANSWER ★★
WE KNOW THAT
A=12
B=16
C=?
A+B×C=56
SUBSTITUTE THE VALUE OF A AND B
12+16×C=56
12+16C=56
16C=56-12
16C=44
C=44/16
C=2.75
NOW WE HAVE TO FIND THAT
C+A×B
=2.75+12×16
=2.75+192
=194.75
SO FRIEND YOUR ANSWER IS 2.75;194.75
HOPE IT HELPS YOU AND PLEASE MARK AS BRAINLIEST
☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺
WE KNOW THAT
A=12
B=16
C=?
A+B×C=56
SUBSTITUTE THE VALUE OF A AND B
12+16×C=56
12+16C=56
16C=56-12
16C=44
C=44/16
C=2.75
NOW WE HAVE TO FIND THAT
C+A×B
=2.75+12×16
=2.75+192
=194.75
SO FRIEND YOUR ANSWER IS 2.75;194.75
HOPE IT HELPS YOU AND PLEASE MARK AS BRAINLIEST
☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺☺
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