Question

If a=12 and d=-3 find the first three term of Arthemetic progression​

Answer 1

AP=a+(n-1)d

=12+(3-1)×(-3)

=12+2×(-3)

=12-6

=6

Answer 2

Answer:

12,9,6,....

Step-by-step explanation:

nth term of an A.P = a+(n-1)d

Given a = 12 , d = -3

An A.P = a,a+d,a+2d,....

First term = a = 12

Second term = a+(2-1)d = a+d = 12-3 = 9

Third term = a+(3-1)d = a+2d = 12 + 2(-3) = 12 - 6 = 6

Hence A.P = 12,9,6,.....