Question

If a= 12, b = 8 and c = 5, show that a - (b - c) = (a - b) - c.
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Answer 1

lhs = a - (b - c)

$solving \: lhs \: when \\ a = 12 \\ b = 8 \\ c = 5 \\ \\ lhs \: = a - (b - c) \\ = 12 - (8 - 5) \\ = 12 - 3 \\ = 9 \\ \\ lhs \: = 9$

rhs = (a-b) - c

$solving \: rhs \: when \\ a = 12 \\ b = 8 \\ c = 3 \\ \\ rhs = (a-b) - c \\ = (12 - 8) - 3 \\ = 4 - 3 \\ rhs \: = 1$

since,

9 is not equal to 1

therefore,

lhs is not equal to rhs

Answer 2

$a - (b - c) = (a - b) - c \\ putting \: the \: values \: of \: a \: b \: and \: c \\ 12 - (8 - 5) = (12 - 8) - 5 \\ 12 - 3 = 4 - 5 \\ 9 = - 1 \\ here \: 9 \: is \: not \: equal \: to \: - 1. \\ so ...\: a - (b - c)is \: also \: not \: equal \\ to \: (a - b) - c$

Hope this is ur answer...