If a 12 V battery is connected to the arrangement of resistances given below, calculate (i) the total effective resistance of the arrangement and (ii) the total current flowing in the circuit current through 10 ohm resistor
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Answered by
5
Explanation:
1)Rs = 30 and 30
1/rp= 1/30 +1/30
= 2/30
rp= 15 ohm
2) v=ir
12= i * 10
i =6/5 A
Answered by
6
Answer:
i) total resistance in 1st series = 10 +20=30 ohm.
total resistance in 2nd series= 5 +25=30 ohm.
total resistance in parallel =1/30+1/30=2/30=1/15.
resistance=15 ohm.
ii) potential difference ( v) =12v
R=10 ohm
we know that, v=IR
so, 12= I×10
I= 12/10=6/5
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