Question

If a 12 V battery is connected to the arrangement of resistances given below, calculate (i) the total effective resistance of the arrangement and (ii) the total current flowing in the circuit current through 10 ohm resistor

Answer 1

Explanation:

First they are connected in series show 10 ohm + 20 ohm that is equal to 30 then next in next diagram they are connected in Paris show 5 ohm + 25 to 30 Ohm then total resistance is equal to their in parallel so1 by 30 ohm + 1 by 30 Ohm that's equal to 15 Ohm so the total resistance is 15 Ohm the current passing through 10 ohm is equal to V by are equal to 12 by 10 is equal to 1.2 ampere

Answer 2

Hey Here is Answer:

For Series

Req = R₁ +R₂

Req = 10 + 20

Req = 30 ohm

For Series

Req = R₁ + R₂

Req = 5 + 25

Req = 30 ohm

For parallel

1/Req = 1/R₁ +1/R₂

1/Req = 1/30 + 1/30

1/Req = 2/30

Req = 30/2 ⇒ 15 ohm

Current in 10 ohm Resistor

I = V/R

I = 12 / 10

I = 1.2 A

Current in Whole Circuit

I = V/R

I = 12/15

I = 0.8 A