Question

if a 12 volt battery is connected to the arrangement of resistance given calculate the total effective resistance of the arrangement the total current flowing in the circuit

Answer 1

Rs=10+20=30

Rs=5+25=30

1/Rp=1/ 30+1/30=2/30

Rp=15;R=15

Then

V=12v

I= ?

V=IR

12/15=I=0.8

Answer 2

Answer:

R = 15 Ω

I = 0.8 Ampere

Step-by-step explanation:

From the given figure, we can say that ;

R1 and R2 are in the series, for series we add resistance simply as shown below,

R1 + R2 = ( 10 + 20 ) Ω

⇒ R1 + R2 = 30 Ω

And, Resistance R3 and R4 are in the series, therefore

R3 + R4 = ( 5 + 25 ) Ω

⇒ R3 + R4 = 30 Ω

Now, R1 + R2 and R3 + R4 are parallel resistors,

⇒ 1 / 30 + 1 / 30

⇒ 1 + 1 / 30

⇒ 2 / 30

⇒ 1 / 15

Hence, total resistance = 15 Ω

We know that,

V = IR

[ ∵ where, V = volt, I = current, R = resistance]

⇒ 12 = I * 15

⇒ I = 12 / 15

⇒ I = 0.8 Ampere

Hence, total resistance is 15 Ω and total current flowing is 0.8 Ampere.