)If a 1200 W electric iron is used daily for 30 minutes, Find total time in secs. for which electricity is consumed in the month of June?
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Given that,
Power =1200W=1.2kWh
Time = 30 min / day × 30 days =0.5h×30= 15 h
Energy =Power×Time=1.2×15= 18kWh.
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Answer
ᴘᴏᴡᴇʀ = 1200ᴡ
ᴛɪᴍᴇ = 30ᴍɪɴ / ᴅᴀʏ × 30
ᴅᴀʏꜱ = 0.5ʜ × 30 = 15ʜ
ᴇɴᴇʀɢʏ = ᴘᴏᴡᴇʀ × ᴛɪᴍᴇ
= 1.2 × 15
= 18ᴋᴡʜ
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