Question

if a 12v battery is connected to the arrangment of resistances shown in the figure , calculate
1. the total effective resistance of the arrangement
2.total current flowing in the circuit

Answer 1

$\huge\fcolorbox{black}{aqua}{Solution:-}$

✏️ Answer:

★ R = 15 Ω

★ I = 0.8 Ampere

✏️ Explanation:-

★ From the given figure, we can say that ;

• R1 and R2 are in the series, for series we add resistance simply as shown below,

R1 + R2 = ( 10 + 20 ) Ω

⇒ R1 + R2 = 30 Ω

And, Resistance R3 and R4 are in the series, therefore

R3 + R4 = ( 5 + 25 ) Ω

⇒ R3 + R4 = 30 Ω

Now, R1 + R2 and R3 + R4 are parallel resistors,

⇒ 1 / 30 + 1 / 30

⇒ 1 + 1 / 30

⇒ 2 / 30

⇒ 1 / 15

Hence, the net equivalent resistance = 15 Ω

We know that,

V = IR

[ ∵ where, V = volt, I = current, R = resistance]

⇒ 12 = I × 15

⇒ I = 12 / 15

⇒ I = 0.8 Ampere

Hence, total resistance is 15 Ω and total current flowing is 0.8 Ampere.

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I hope this helps! :)