If a 12v battery is connected to three resistor 1 ohm, 2 ohm , 3 ohm in series , then find the total current flow through of circuit. And also find potential difference across each resis
Answers
Answered by
2
Answer:
v=12v
r=1+2+3ohm
=6ohm
v=ir
12=i×6
i=12÷6
i=2ampere
Answered by
0
Answer:
2A
Explanation:
in series connection the flowing of current remain in all resistor
we know that Rs=r1+r2+r3
R=1+2+3=6
then according to ohm's law
I =V/R
then I = 12/6=2A
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