If a 12v battery is connected to three resistors 1 ohm, 2 ohm, 3 ohm in series. What is the total current and potential difference in the current?
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it is equal to 6 omh
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V = 12
R1 = 1 ohm
R2 = 2 ohm
R3 = 3 ohm
V = IR
12 = I * 1+2+3
12 = I * 6
12/6 = I
2 = I
V1 = I*R1
V1 = 2*1
V1 = 2
V2 = I*R2
V2 = 2*2
V2 = 4
V3 = I*R3
V3 = 2*3
V3 = 6
V = V1 + V2 + V3
12 = 2+4+6
12 = 12
R1 = 1 ohm
R2 = 2 ohm
R3 = 3 ohm
V = IR
12 = I * 1+2+3
12 = I * 6
12/6 = I
2 = I
V1 = I*R1
V1 = 2*1
V1 = 2
V2 = I*R2
V2 = 2*2
V2 = 4
V3 = I*R3
V3 = 2*3
V3 = 6
V = V1 + V2 + V3
12 = 2+4+6
12 = 12
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