if a=17 b=15 c=13 then a^2+b^2+c^2-2ab-2bc-2ca = ?
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Answered by
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17^2+15^2+13^2-2×17×15-2×15×13-2×13×17
= infinity
= infinity
Answered by
0
hii friend◆◆◆◆◆
here is your answer
Given that
a=17, b=15, c=13
now according to question. ....
a^2+b^2+c^2-2ab-2bc-2ca
putting the value of a, b & c
then
=( 17)^2+(15)^2+(13)^2-2.17.15-2.15.13-2.13.17
=289+225+169-510-390-442
=683--1342
=-659
....♥♥♥thank u♥♥♥....
I think it will help you then you mark me brainlist please please please. ....
___________________________
here is your answer
Given that
a=17, b=15, c=13
now according to question. ....
a^2+b^2+c^2-2ab-2bc-2ca
putting the value of a, b & c
then
=( 17)^2+(15)^2+(13)^2-2.17.15-2.15.13-2.13.17
=289+225+169-510-390-442
=683--1342
=-659
....♥♥♥thank u♥♥♥....
I think it will help you then you mark me brainlist please please please. ....
___________________________
pkrajput0007:
Answer giving 12 not 659
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