Math, asked by kumarmohit181004, 3 months ago

If A =1i/√2 + bj is a unit vector, then value of b:​

Answers

Answered by senboni123456
0

Answer:

Step-by-step explanation:

We have,

\tt{\vec{A}=\dfrac{1}{\sqrt{2}}\,\hat{i}+b\hat{j}}

Since the given vector is a unit vector, so,

\sf{|\vec{A}|=1}

\sf{\implies\,\sqrt{\bigg(\dfrac{1}{\sqrt{2}}\bigg)^2+(b)^2}=1}

\sf{\implies\,\dfrac{1}{2}+b^2=1}

\sf{\implies\,b^2=1-\dfrac{1}{2}}

\sf{\implies\,b^2=\dfrac{1}{2}}

\sf{\implies\,b=\pm\dfrac{1}{\sqrt{2}}}

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