If A=[2 0 1 ], then the rank of AA t is
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Answer:
Given A=[
2
0
1
]
1×3
A
T
=
⎣
⎢
⎢
⎡
2
0
1
⎦
⎥
⎥
⎤
3×1
AA
T
=[
2
0
1
]
1×3
⎣
⎢
⎢
⎡
2
0
1
⎦
⎥
⎥
⎤
3×1
=[4+0+1]
1×1
=[5]
1×1
det(AA
T
)=5
=0
∴ Rank AA
T
=1.
Step-by-step explanation:
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