Question

if a=√2+1/√2-1 and b=√2-1/√2+1,then find the value of a²+b²-4ab

Answer 1

a=_/2+1×_/2+1/(_/2)^2_(1)^2
2+1+2_/2/2-1
3+_/2
b= 3-_/2
a×b = (3)^2-_/2^2
9-2=7
4ab= 21
(3+_/2 )^2 +(3-_/2)^2 -21
9+2+6_/2+9+2-6_/2-21
11+11-21
22-21=1

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