If a^2 +1/a^2 =102 then find a-1/a
_NOTE:-_ ^2 THIS SYMBOL INDICATES THE SQUARE
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Answer(:a+1/a)^2-2=102
(a+1/a)^2=100
a+1/a=√100=10
rabindra6:
sorry not marked as brainliest because u've not explained step wise I've the answer but I want the steps
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a^2 + 1/a^2 = 102
To find a - 1/a
=>a^2 + 1/a^2 - 2 + 2 = 102
=>a^2 + (1/a)^2 - 2 + 2 = 102
[Now it has become a identity i.e. a^2 + b^2 - 2ab = (a-b)^2]
=>(a - 1/a)^2 + 2 = 102
=>(a - 1/a)^2 = 102 - 2
=>(a - 1/a)^2 = 100
=>a - 1/a = root 100 [whole square will go on right hand side and will become square root]
=>a - 1/a = 10
Please mark as brainliest.
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