Math, asked by avinashgupta57, 1 year ago

If a^2+1÷a^2 = 23, find the value of (a+1÷a)​

Answers

Answered by BrainlyPopularman
6

Answer:

 {a}^{2}  +  \frac{ 1 }{ {a}^{2} }  = 23 \\  {(a +  \frac{1}{a} )}^{2}  =  {a}^{2}  +   \frac{1}{ {a}^{2} }  + 2 \\  {(a +  \frac{1}{a} )}^{2}  = 23 + 2 = 25 \\ \\  a +  \frac{1}{a}   =  |5|

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