Question

if a^2+1÷a^2=27,then value of a-1÷a is​

Answer 1

Step-by-step explanation:

a =1/square root of 26.

Now put the value of a in the required expression

Answer 2

Answer : 5 ✔✔

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Solution :

Given that :

${a}^{2} + \frac{1}{ {a}^{2} } = 27$

To find :

$a - \frac{1}{a}$

As we know that :

${(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab$

Such as :

${(a - \frac{1}{a}) }^{2} = {a}^{2} + \frac{1}{ {a}^{2} } - 2.a. \frac{1}{a} \\ \\ = > {(a - \frac{1}{a}) }^{2} = 27 - 2 \\ \\ = > {(a - \frac{1}{a}) }^{2} = 25 \\ \\ = > (a - \frac{1}{a} ) = \sqrt{25} = 5$

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Hope it helps ☺

Fóllòw Më ❤