Math, asked by AdityaJadhav44, 8 months ago

If a^2 + 1/a^2 = 47 find a^3 + 1/a^3​

Answers

Answered by yashica62
6

Step-by-step explanation:

a^2 + 1/a^2 =47

(a+1/a)^2 =47

a^2 + 1/a^2 + 2*a*1/a =47

a and 1/a will be cut

a^2 + 1/a^2 =47 + 2 = 49

a + 1/a = 7

a^3 +1/a ^3 = 7^3

a^3 + 1/a^3 + 3ab = 343

a^3 + 1/a^3 + 3 * a^3 * 1/a^ 3 = 343

a and 1/a will be 7 as we do in first

a^3 +1/a^3 = 343 - 7*3

a^3 +1/a^3 = 322

may be it is helpful!!!!

Answered by sologamer5618
0

Answer:

322

Step-by-step explanation:

a^2 + 1/a^2 =47

(a+1/a)^2 =47

a^2 + 1/a^2 + 2*a*1/a =47

a and 1/a will be cut

a^2 + 1/a^2 =47 + 2 = 49

a + 1/a = 7

a^3 +1/a ^3 = 7^3

a^3 + 1/a^3 + 3ab = 343

a^3 + 1/a^3 + 3 * a^3 * 1/a^ 3 = 343

a and 1/a will be 7 as we do in first

a^3 +1/a^3 = 343 - 7*3

a^3 +1/a^3 = 322

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