If A (2, -1), B (-1,3) and C (6,7) are the tops of ΔABC. Find the length of the median drawn from the top B.
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As From B median is drawn To AC
So it will intersect at mid point of AC
Mid point of AC
A( 2,-1) C( 6,7)
is ( 2 + 6)/2 , ( -1 + 7)/2
= 8/2, 6/2
= 4,3
So distance between B (-1,3) and (4,3)
( As here y coordinate same So its simply ( 4-(-1) = 5
Or
√ ( 4 - ( -1))^2 + ( 3-3)^2
= √ 5^2.
= 5
So it will intersect at mid point of AC
Mid point of AC
A( 2,-1) C( 6,7)
is ( 2 + 6)/2 , ( -1 + 7)/2
= 8/2, 6/2
= 4,3
So distance between B (-1,3) and (4,3)
( As here y coordinate same So its simply ( 4-(-1) = 5
Or
√ ( 4 - ( -1))^2 + ( 3-3)^2
= √ 5^2.
= 5
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