If A(2,1) ,B(5,4) and C (7,c) are collinear points find the possible value of c .
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Step-by-step explanation:
Given points are A(x,2)B(−3,−4)C(7,−5)
(x
1
,y
1
)=(x,2),(x
2
,y
2
)=(−3,−4)(x
3
,y
3
)=(7,−5)
x
1
[y
2
−y
3
]+x
2
[y
3
−y
1
]+x
3
[y
1
−y
2
]=0
x[(−4)−(−5)]+(−3)[(−5)−2]+7[2−(−4)]=0
x(−4+5)−3(−5−2)+7(2+4)=0
x(1)−3(−7)+7(6)=0
x+21+42=0
x+63=0
x=−63
∴ The value of x is −63.
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