if A(-2,1) B(9,0) C (4,b) and D(1,2) are the verticles of a parallelogram ABCD, find the value of a and b. hence find the lenght of its sides.
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Hii friend,
ABCD IS A PARALLELOGRAM.
SIDES OF PARALLELOGRAM AB , BD, AC, CD
A(-2,1) , B(9,0) , C(4,B) , D(1,2).
AD AND BC ARE THE DIAGONALS OF PARALLELOGRAM.
WE KNOW THAT,
THE DIAGONALS OF PARALLELOGRAM BISECT EACH OTHER AT O.
O IS THE MIDPOINT OF DIAGONALS AD AND BC.
THEREFORE,
THE COORDINATES OF O IS = X1+X2/2 , Y1+Y2/2.
= (-2+1/2 , 1+2/2 ) = (-1/2, 3/2).
AND,
O IS THE MIDPOINT OF BC.
THEREFORE,
COORDINATES OF POINT OF = X1+X2/2 , Y1+Y2/2.
= (9+4/2, 0+b/2
= (13/2, b/2) ARE THE COORDINATES OF POINT O.
BUT ,
THE COORDINATES OF POINT O IS O(-1/2),(3/2).
THEREFORE,
b/2 = 3/2
2b = 6
b = 6/2 = 3.
ABCD IS A PARALLELOGRAM.
SIDES OF PARALLELOGRAM AB , BD, AC, CD
A(-2,1) , B(9,0) , C(4,B) , D(1,2).
AD AND BC ARE THE DIAGONALS OF PARALLELOGRAM.
WE KNOW THAT,
THE DIAGONALS OF PARALLELOGRAM BISECT EACH OTHER AT O.
O IS THE MIDPOINT OF DIAGONALS AD AND BC.
THEREFORE,
THE COORDINATES OF O IS = X1+X2/2 , Y1+Y2/2.
= (-2+1/2 , 1+2/2 ) = (-1/2, 3/2).
AND,
O IS THE MIDPOINT OF BC.
THEREFORE,
COORDINATES OF POINT OF = X1+X2/2 , Y1+Y2/2.
= (9+4/2, 0+b/2
= (13/2, b/2) ARE THE COORDINATES OF POINT O.
BUT ,
THE COORDINATES OF POINT O IS O(-1/2),(3/2).
THEREFORE,
b/2 = 3/2
2b = 6
b = 6/2 = 3.
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