If a(-2,1) b(a,b)and c(4,1) are collinear find a andb
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area of triangle =
½[a1(b2-b3)+a2(b3-b1)+a3(b1-b2)
as points are collinear the area is zero here
a1=-2. b1=1
a2=a. b2=b
a3=4. b3=1
so putting value in eq
a=1 b=1
½[a1(b2-b3)+a2(b3-b1)+a3(b1-b2)
as points are collinear the area is zero here
a1=-2. b1=1
a2=a. b2=b
a3=4. b3=1
so putting value in eq
a=1 b=1
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