Math, asked by sohail345jdjd, 10 months ago

if a= 2^2×3^3×5^4 and b=2^3×3^2×5 then find hcf of(a,b) and lcm of(a,b)​

Answers

Answered by priyasharma89
41

H.C.F. = 2^2 × 3^2 ×5

= 4×9 ×5

= 180

L.C.M.= 2^3 × 3^3 ×5^4

= 8× 27 × 625

= 135000

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Answered by erinna
25

H.C.F. of(a,b) is 180 and L.C.M. of(a,b)​ is 135000.

Step-by-step explanation:

The given numbers are

a= 2^2\times 3^3\times 5^4

b=2^3\times 3^2\times 5

Highest Common Factor of a and b : It is a largest positive integer that divides both a and b.

H.C.F. = 2^2 \times 3^2 \times 5

H.C.F. = 4 \times 9 \times 5

H.C.F. =180

Least Common Multiple of a and b : It is a smallest positive integer that is divisible by both a and b.

L.C.M.= 2^3 \times  3^3 \times 5^4

L.C.M.= 8 \times 27 \times 625

L.C.M.= 135000

Therefore,  H.C.F. of(a,b) is 180 and L.C.M. of(a,b)​ is 135000.

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