Question

If (a-2)^2+(b-3)^2+(c-11)^2=0 find √(a+b+c)= ?

Answer 1

formula if x^2+y^2+z^2=0 then x=0,y=0,z=0

therefore a=2,b=3,c=11

√a+b+c=√2+3+11=√16=4

fo llow me