If A(2,2),B(8,6),P(4,2),Q(10,6) are any four points then prove that AB = PQ in length...
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We know that the diagonals of a parallelogram bisect each other. So, coordinates of the mid-point of diagonal AC are same as the coordinates of the mid-point of diagonal BD.
∴(26+9,21+4)=(28+p,22+3)
⇒(215,25)=(28+p,25)
⇒215=28+p⇒15=8+p⇒p=7
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Answer:
Yes they are equal in length
Explanation:
first you have to find the distance between two point by using the formula √(x2-x1)^2+(y2-y1)^2
for the point AB =√(8-2)^2+(6-2)^2
AB=√100
AB=10
AND similarly we can find PQ
which is also equal to 10
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