Question

If a^2-2a+1=0 then the value of a is--​

Answer 1

Answer:

a = 1

Step-by-step explanation:

==: a² - 2a + 1 = 0

==: a² - a - a + 1 = 0

==: a (a - 1) - 1 (a - 1) = 0

==: (a - 1) (a - 1) = 0

==: a = 1

Pls mark my answer as brainlist

Pls follow me

Answer 2

Step-by-step explanation:

${a}^{2} - 2a + 1 = 0$

${a}^{2} - (a + a) + 1 = 0$

$a(a - 1) - 1(a - 1) = 0$

therefore,

$a = 1$