Math, asked by yuvaranihemanth, 9 months ago

If a^2-2a-3 is a factor of a^4+pa^3+qa^2+12a-9 then find the value of p^2-2q-3

Answers

Answered by MaheswariS
3

\textbf{Factor theorem:}

\text{(x-a) is a factor of f(x) iff f(a) =0}

\textbf{Given:}

a^2-2a-3\;\text{is a factor of}\;a^4+p\,a^3+q\,a^2+12a-9

\textbf{To find:}

\text{The value of $p^2-2q-3$}

\textbf{Solution:}

\text{Let}\;f(a)=a^4+p\,a^3+q\,a^2+12a-9

a^2-2a-3=(a-3)(a+1)

\textbf{Since (a-3) is a factor of f(a), we have f(3)=0}

\implies\,3^4+p\,3^3+q\,3^2+12(3)-9=0

\implies\,81+27\,p+9\,q+27=0

\implies\,27\,p+9\,q=-108

\implies\bf\,3\,p+q=-12.....(1)

\textbf{Since (a+1) is a factor of f(a), we have f(-1)=0}

\implies\,(-1)^4+p\,(-1)^3+q\,(-1)^2+12(-1)-9=0

\implies\,1-p+q-21=0

\implies\bf\,-p+q=20.......(2)

\text{Subtracting (2) from (1), we get}

4\,p=-32

\implies\bf\;p=-8

(2)\implies\bf\,q=12

\text{Now,}

\bf\,p^2-2q-3

=(-8)^2-2(12)-3

=64-24-3

=37

\textbf{Answer:}

\textbf{The value of $\bf\,p^2-2q-3$ is 37}

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Answered by nandini1627
3

Answer:

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