Question

if a+2 = 2y and b2 = ac then show that ay-z, bz - x, cx-y=1​

Answer 1

Step-by-step explanation:

A^x= b^y = c^z , from this if we like to express A & c in terms of b —-

A^x = b^y, => A = b^(y/x) , similarly , as c^z = b^y Therefore , c = b^(y/z). It is also given that ——

b^2 = Ac,

or,b^2 = {b^(y/x)}*{b^(y/z)} ( putting the value of A & c defined in terms of b )

Or, b^2= b^(y/x+y/z)

or, b^2 = b^{( yz +xy)/xz }

or, (xy + yz)/xz =2 (as base on the both side equals (b) , power is equal)

or, xy + yz = 2xz

or, y(x+z) = 2xz

So, y = 2xz/(x+z)

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