If a=2+√3/2-√3 and b=2-√3/2+√3 find the value of a^2-ab+b^2
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here is your answer mate...
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Solution :
a - b√3
= ( 2-√3)/(2+√3)
= [(2-√3)(2-√3)]/[(2+√3)(2-√3)]
= (2-√3)²/[2²-(√3)²]
= [2²-2×2×√3+(√3)²]/(4-3)
= 4 - 4√3 + 3
= 7 - 4√3
Therefore ,
a - b√3 = 7 - 4√3
a = 7 , b = 4
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