if a=2*3×3, b=2×3×5, c=3*a×5 and LCM (a,b c)=2*3×3*2×5, then n=
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Answered by
4
Answer:
no
Step-by-step explanation:
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Answered by
5
Answer:
N=2
Step-by-step explanation:
a = 2³ × 3¹
b = 2¹ × 3¹ × 5¹
c = 3ⁿ × 5¹
LCM = 2³ × 3ⁿ × 5 ----(1)
/* Product of the smallest power of each common prime factor of the numbers */
LCM = 2³ × 3² × 5 ----(2)[given]
Now , compare (1) & (2) , we get
n = 2
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