Question

if a = 2^3*3, b = 2*3*5, c = 3^n *5 and the LCM (a,b,c)= 2^3 * 3^2 * 5 Then find the value of n?

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Value of n = 2

Step-by-step explanation:

a = 2³ × 3¹

b = 2¹ × 3¹ × 5¹

c = 3ⁿ × 5¹

LCM = 2³ × 3ⁿ × 5 ----(1)

/* Product of the smallest power of each common prime factor of the numbers */

LCM = 2³ × 3² × 5 ----(2)[given]

Now , compare (1) & (2) , we get

n = 2

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