If A {2, 3, 4, 5), B= {1, 2, 3} and C = {5, 6}, then verify
n( AUBUC)+ n( AO B)+ n( B0C)+ n(COA) = n( A)+ n( B) + n(C)+ n(ACB0C)
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(2+3+4+5)1+2+3=6and 14 answer is 6 and 14
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